In the previous lectures, you have learnt the Boolean algebra and K-Map methods of solving Boolean expressions.

These methods are simple and easy for less number of variables say upto four. But for more than 4 variable equations, these become tedious. So, another method known as Quine Mc-Clusky or Tabulation Method is used for solving Boolean expression involving four or more variables.

Quine Mc-Clusky or Tabulation Method

This is again a simple method but requires lot of concentration while looking for minterms with 1-bit change. A little distraction of mind will lead to committing a mistake.

Various steps involved in simplification are:

  1. Preparing index value based on number of 1’s in the minterms of the equation including don’t care terms.
  2. Rearranging the minterms as per index value
  3. Checking minterms from one group to another for a 1-bit change and ticking such terms.
  4. Repeating step-3 till such time no further pairing of minterms are possible. All such terms are called as prime implicants terms
  5. Preparing PI chart to find essential prime implicants


Simplify Y(A,B,C,D) = ∑m(0,2,3,6,7,8,10,12,13) using McClusky or the Tabulation method


Step-1: Prepare index value (i.e. find number of 1’s in each minterm)

minterm mo M2 M3 M6 M7 M8 M10 M12 M13
Binary 0000 0010 0011 0110 0111 1000 1010 1100 1101
Index 0 1 2 2 3 1 2 2 3


Step-2: Group the minterms as per index value

At this point, one can start combining minterms with other minterms. If two terms vary by only a single digit changing, that digit can be replaced with a dash indicating that the digit doesn’t matter. Terms that can’t be combined any more are marked with an asterisk (*)

Figure-1: Finding the Prime Implicants

Step-3: Preparing PI Char for finding Essential Prime Implicants

Figure-2: Prime Implicant Chart

So, the final solution of the expression Y(A,B,C,D) = ∑m(0,2,3,6,7,8,10,12,13) is:

Y   = A’C   +  B’D’    +  ABC’



Solve the following Boolean expressions using Tabulation method

  1. Y(A,B,C,D) = ∑m(0,1,2,5,6,7,8,9,10,14)
  2. Y(A,B,C,D) = ∑m(0,5,8,9,10,11,14, 15)
  3. Y(A,B,C,D) = ∑m(0,1,3,7,8,9,11,15)
  4. Y(A,B,C,D) = ∑m(4,6,9,10,11,13) + ∑d(2,12,15)


By admin

Leave a Reply

Your email address will not be published. Required fields are marked *

error: Content is protected !!